REFLECTION OF MATH

HOW TO SOLVE PROBLEM?

Word problems can be very challenging to many students and some of the basic things to think about when we trying to solve the word problem is to figure out what about the facts and what is being outs for.

Example:
A college student plans to spend $420 on books for one semester. He also plans to spend $20 per week on pizza. The Fall semester is 18 weeks long. How much will he need for books and pizza?

Solution:
Basically, we have the fact that the student is going to spending some money. He's spending $420 for books and $20 per week on pizza.  And then we know  there is 18 weeks long for this semester.
So, we are going to take $20 he's spending each week and multiply times 18 the number of week.
So he's spending $360 on pizza and $420 on books for this semester.
If we want to know how much he's spend on books and pizza in this semester, we need to add $360 and $420 and get the answer is $780. So, he will need $780 for books and pizza.

this video tells us about how to solve word problem which usually faced by the children. it is also helpful for teacher to help him to teach the students related to solve the word problem.

the 'word problem' related to every single parts of daily life. it related to many things and finally required a math operation to solve the problem.

many students usually get scared of word problem because it consists of many words that makes them confused. in this video, there is a new way to brake up the problem that is the use of 'buck'. buck itself is easy to understand because it closely related to money.

buck consists of four big important parts, they are B- box the information U-underline the information needed C-circle the vocabulary K-knock out the unneeded information because many students usually get confused by too much word.

there is an example there. how to solve the prblem?you can use the BUCK system to SOS: simplify, organize, and solve the problem.

so we can start by  B: box the question, how many t-shirts are sold in a week ?

U: the underlined information are three, 10 minutes and 9am until 9pm everyday.

C:the circle word that needed to aware, they are minutes, everyday, and week.

K: and the unneeded information that may cause a problem are $19.95, 45 , and $24.95.

so the informations needed to solve the problem are:

60 minutes in an hour

12 hours from 9am to 9pm

so we have to multiply 12 times 60=720 minutes per day the shop is open

a t-shirt sold every ten minutes so we will devide 720 devide 10=72 per day

so in week we should multiply 72 times 7=504

and finally we can get the answer that the shop sells 504 t-shirts per week

there is another example that might cause people think that he is not in the end of the problem, so we should pay attention to the question.

so the formula of BUCK are:

B-how much money should maria bring

U- the info i need to know is a pair of shoes, the original price is $ 80.00 and discount of 20%

C-the vocabulary that i need to understand to solve the problem is the meaning of the original and discount.

and the information which do not needed are shoe store and last one week.

so the informations we need to solve the problem are:

the original proce is $80.00

and the discount is 20%, it means that the new price should be smaller than the original price.

so 80.00 times 20% = $16.00

and the new prices comes from the original price $80.00 minus the discount of $16.oo = $ 64.00

so the answer is that maria needs to bring at least at $64.00 with to the shoe store.

finally, what you need to underline when using BUCK when solving word problems are:

Box the question

Underline the information needed

Circle the vocabulary

Knock out information not needed.

there are some new vocabulary in this video which you can learn using your own word, they are:

-original cost

-discount

-measurements----minutes, hours, days, week

This video is going to show how to solve puzzle and riddles (otherwise known as word problems) using two variables.

and there will be two more examples. the first question.

so we need to replace the 1st number with X and the 2nd # with y.

so we can make a formula for those two questions with:

1st #: X x+2y=23

2nd #: Y                2x+y=31

and we can use one of those formula to solve the problem.

let say i will be with the first formula

x+2y=23 ( and i will subtract 2y for both side) so,

 -2y  -2y so,

x=23-2y

so lets move the second formula that is 2x+y=31 and replace the x with the formula above

2x+y=31

2(23-2y)+y equals 31 (so we have one variable here)

46-4y+y equals 31 ( and we can simplify)

  -3y+46 equals 31 ( and i think i will make it positif with adds +3y for both side, and make it simple with subtracts 31 for both number also)

  +3y-31        -31+3y (so the answer will be)

      15=3y so y equals 5.

so lets find the answer of the other formula

x=23-2y ( and subtitute y with 5, so)

 =23-2(5)

 =23-10

x=13

So the number are 13 and 5

Again we have the situation to find the first and the second number. And we write the two equation. The first number is x and the second number is y.

The first number plus 2 more than 3 times the second equation is 18. So, x + (3y + 2) = 18.
We can simplify the second equation to be x+3y= 16. So, we have x+3y=16 and x+y= 16 .
Now, we have to find x and y. We may multiply the second equation with -1. So it will be
x+3y= 16
-x-y= -16. We get 2y=0 and y=0.
Now, we apply y=0 on the first equation. We get x+y= 16
x+0= 16, so x=16.

 Let's check.
For the first equation, 0+16=16. For the second equation, 16+2=18. These are right.

So the numbers are 16 and 0.